3.5.44 \(\int x^{3/2} (a+b x)^3 \, dx\)

Optimal. Leaf size=51 \[ \frac {2}{5} a^3 x^{5/2}+\frac {6}{7} a^2 b x^{7/2}+\frac {2}{3} a b^2 x^{9/2}+\frac {2}{11} b^3 x^{11/2} \]

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Rubi [A]  time = 0.01, antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {43} \begin {gather*} \frac {6}{7} a^2 b x^{7/2}+\frac {2}{5} a^3 x^{5/2}+\frac {2}{3} a b^2 x^{9/2}+\frac {2}{11} b^3 x^{11/2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^(3/2)*(a + b*x)^3,x]

[Out]

(2*a^3*x^(5/2))/5 + (6*a^2*b*x^(7/2))/7 + (2*a*b^2*x^(9/2))/3 + (2*b^3*x^(11/2))/11

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int x^{3/2} (a+b x)^3 \, dx &=\int \left (a^3 x^{3/2}+3 a^2 b x^{5/2}+3 a b^2 x^{7/2}+b^3 x^{9/2}\right ) \, dx\\ &=\frac {2}{5} a^3 x^{5/2}+\frac {6}{7} a^2 b x^{7/2}+\frac {2}{3} a b^2 x^{9/2}+\frac {2}{11} b^3 x^{11/2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 39, normalized size = 0.76 \begin {gather*} \frac {2 x^{5/2} \left (231 a^3+495 a^2 b x+385 a b^2 x^2+105 b^3 x^3\right )}{1155} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^(3/2)*(a + b*x)^3,x]

[Out]

(2*x^(5/2)*(231*a^3 + 495*a^2*b*x + 385*a*b^2*x^2 + 105*b^3*x^3))/1155

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IntegrateAlgebraic [A]  time = 0.01, size = 47, normalized size = 0.92 \begin {gather*} \frac {2 \left (231 a^3 x^{5/2}+495 a^2 b x^{7/2}+385 a b^2 x^{9/2}+105 b^3 x^{11/2}\right )}{1155} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^(3/2)*(a + b*x)^3,x]

[Out]

(2*(231*a^3*x^(5/2) + 495*a^2*b*x^(7/2) + 385*a*b^2*x^(9/2) + 105*b^3*x^(11/2)))/1155

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fricas [A]  time = 0.88, size = 40, normalized size = 0.78 \begin {gather*} \frac {2}{1155} \, {\left (105 \, b^{3} x^{5} + 385 \, a b^{2} x^{4} + 495 \, a^{2} b x^{3} + 231 \, a^{3} x^{2}\right )} \sqrt {x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)*(b*x+a)^3,x, algorithm="fricas")

[Out]

2/1155*(105*b^3*x^5 + 385*a*b^2*x^4 + 495*a^2*b*x^3 + 231*a^3*x^2)*sqrt(x)

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giac [A]  time = 0.99, size = 35, normalized size = 0.69 \begin {gather*} \frac {2}{11} \, b^{3} x^{\frac {11}{2}} + \frac {2}{3} \, a b^{2} x^{\frac {9}{2}} + \frac {6}{7} \, a^{2} b x^{\frac {7}{2}} + \frac {2}{5} \, a^{3} x^{\frac {5}{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)*(b*x+a)^3,x, algorithm="giac")

[Out]

2/11*b^3*x^(11/2) + 2/3*a*b^2*x^(9/2) + 6/7*a^2*b*x^(7/2) + 2/5*a^3*x^(5/2)

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maple [A]  time = 0.00, size = 36, normalized size = 0.71 \begin {gather*} \frac {2 \left (105 b^{3} x^{3}+385 a \,b^{2} x^{2}+495 a^{2} b x +231 a^{3}\right ) x^{\frac {5}{2}}}{1155} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)*(b*x+a)^3,x)

[Out]

2/1155*x^(5/2)*(105*b^3*x^3+385*a*b^2*x^2+495*a^2*b*x+231*a^3)

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maxima [A]  time = 1.34, size = 35, normalized size = 0.69 \begin {gather*} \frac {2}{11} \, b^{3} x^{\frac {11}{2}} + \frac {2}{3} \, a b^{2} x^{\frac {9}{2}} + \frac {6}{7} \, a^{2} b x^{\frac {7}{2}} + \frac {2}{5} \, a^{3} x^{\frac {5}{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)*(b*x+a)^3,x, algorithm="maxima")

[Out]

2/11*b^3*x^(11/2) + 2/3*a*b^2*x^(9/2) + 6/7*a^2*b*x^(7/2) + 2/5*a^3*x^(5/2)

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mupad [B]  time = 0.05, size = 35, normalized size = 0.69 \begin {gather*} \frac {2\,a^3\,x^{5/2}}{5}+\frac {2\,b^3\,x^{11/2}}{11}+\frac {6\,a^2\,b\,x^{7/2}}{7}+\frac {2\,a\,b^2\,x^{9/2}}{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)*(a + b*x)^3,x)

[Out]

(2*a^3*x^(5/2))/5 + (2*b^3*x^(11/2))/11 + (6*a^2*b*x^(7/2))/7 + (2*a*b^2*x^(9/2))/3

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sympy [A]  time = 1.70, size = 49, normalized size = 0.96 \begin {gather*} \frac {2 a^{3} x^{\frac {5}{2}}}{5} + \frac {6 a^{2} b x^{\frac {7}{2}}}{7} + \frac {2 a b^{2} x^{\frac {9}{2}}}{3} + \frac {2 b^{3} x^{\frac {11}{2}}}{11} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(3/2)*(b*x+a)**3,x)

[Out]

2*a**3*x**(5/2)/5 + 6*a**2*b*x**(7/2)/7 + 2*a*b**2*x**(9/2)/3 + 2*b**3*x**(11/2)/11

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